Revision as of 00:40, 19 November 2023 by Admin (Created page with "'''Solution: E''' The annual payment is <math display = "block">10,000 a_{\overline{10}|0.01} = 10, 000 / 6.14457 = 1627.45</math>. The balance at time 3 is <math display = "block">1627.45 a_{\overline{7}|0.01} = 1627.45(4.8684) = 7923.08.</math>. With one-half year at simple interest, the balance at time 3.5 is 7923.08(1.05) = 8319.23. {{soacopyright | 2023 }}")
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Exercise


ABy Admin
Nov 19'23

Answer

Solution: E

The annual payment is

[[math]]10,000 a_{\overline{10}|0.01} = 10, 000 / 6.14457 = 1627.45[[/math]]

. The balance at time 3 is

[[math]]1627.45 a_{\overline{7}|0.01} = 1627.45(4.8684) = 7923.08.[[/math]]

.

With one-half year at simple interest, the balance at time 3.5 is 7923.08(1.05) = 8319.23.

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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