Revision as of 13:43, 19 November 2023 by Admin (Created page with "'''Solution: B''' <math display = "block"> \begin{aligned} & P_t=I_t \\ & v^{20-t+1}=\left(1-v^{20-t+1}\right) \\ & 2 v^{20-t+1}=1 \\ & v^{21-t}=0.5 \\ & 1.05^{21-t}=2 \\ & (21-t) \ln (1.05)=\ln 2 \\ & t=7\end{aligned} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: B
[[math]]
\begin{aligned} & P_t=I_t \\ & v^{20-t+1}=\left(1-v^{20-t+1}\right) \\ & 2 v^{20-t+1}=1 \\ & v^{21-t}=0.5 \\ & 1.05^{21-t}=2 \\ & (21-t) \ln (1.05)=\ln 2 \\ & t=7\end{aligned}
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.