Revision as of 13:18, 19 November 2023 by Admin (Created page with "'''Solution: E''' Let I be the amount of interest in the first month. <math display = "block"> P_0-m+I=P_1, I=P_1-\left(P_0-m\right) </math> In the first month, the interest <math>P_1-\left(P_0-m\right)</math> was charged on a principal of <math>P_0</math>, so the effective monthly interest rate (expressed as a decimal) of the first loan is <math display = "block">\frac{P_1-\left(P_0-m\right)}{P_0}=\frac{P_1-P_0+m}{P_0}</math>. The nominal annual interest rate (expres...")
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Exercise


ABy Admin
Nov 19'23

Answer

Solution: E

Let I be the amount of interest in the first month.

[[math]] P_0-m+I=P_1, I=P_1-\left(P_0-m\right) [[/math]]

In the first month, the interest [math]P_1-\left(P_0-m\right)[/math] was charged on a principal of [math]P_0[/math], so the effective monthly interest rate (expressed as a decimal) of the first loan is

[[math]]\frac{P_1-\left(P_0-m\right)}{P_0}=\frac{P_1-P_0+m}{P_0}[[/math]]

.

The nominal annual interest rate (expressed as a decimal) for both loans is therefore [math]12\left(\frac{P_1-P_0+m}{P_0}\right)[/math], so the effective daily rate (expressed as a decimal) for the second loan is

[[math]] \frac{12}{365}\left(\frac{P_1-P_0+m}{P_0}\right) [[/math]]

Finally, the effective monthly rate (expressed as a decimal) for the second loan is

[[math]] \left[1+\frac{12}{365}\left(\frac{P_1-P_0+m}{P_0}\right)\right]^{365 / 12}-1 [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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