Revision as of 13:18, 19 November 2023 by Admin (Created page with "'''Solution: E''' Let I be the amount of interest in the first month. <math display = "block"> P_0-m+I=P_1, I=P_1-\left(P_0-m\right) </math> In the first month, the interest <math>P_1-\left(P_0-m\right)</math> was charged on a principal of <math>P_0</math>, so the effective monthly interest rate (expressed as a decimal) of the first loan is <math display = "block">\frac{P_1-\left(P_0-m\right)}{P_0}=\frac{P_1-P_0+m}{P_0}</math>. The nominal annual interest rate (expres...")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: E
Let I be the amount of interest in the first month.
[[math]]
P_0-m+I=P_1, I=P_1-\left(P_0-m\right)
[[/math]]
In the first month, the interest [math]P_1-\left(P_0-m\right)[/math] was charged on a principal of [math]P_0[/math], so the effective monthly interest rate (expressed as a decimal) of the first loan is
[[math]]\frac{P_1-\left(P_0-m\right)}{P_0}=\frac{P_1-P_0+m}{P_0}[[/math]]
.
The nominal annual interest rate (expressed as a decimal) for both loans is therefore [math]12\left(\frac{P_1-P_0+m}{P_0}\right)[/math], so the effective daily rate (expressed as a decimal) for the second loan is
[[math]]
\frac{12}{365}\left(\frac{P_1-P_0+m}{P_0}\right)
[[/math]]
Finally, the effective monthly rate (expressed as a decimal) for the second loan is
[[math]]
\left[1+\frac{12}{365}\left(\frac{P_1-P_0+m}{P_0}\right)\right]^{365 / 12}-1
[[/math]]