Revision as of 19:24, 19 November 2023 by Admin (Created page with "Bond X and Bond Y are n-year bonds with face amount of 10,000 and semiannual coupons, each yielding an annual nominal interest rate of 7% convertible semiannually. Bond X has an annual coupon rate of 6% and redemption value c. Bond Y has an annual coupon rate of 5% and redemption value c + 50. The price of Bond X exceeds the price of Bond Y by 969.52. Calculate n. <ul class="mw-excansopts"><li>14</li><li>17</li><li>23</li><li>34</li><li>46</li></ul> {{soacopyright | 2...")
ABy Admin
Nov 19'23
Exercise
Bond X and Bond Y are n-year bonds with face amount of 10,000 and semiannual coupons, each yielding an annual nominal interest rate of 7% convertible semiannually. Bond X has an annual coupon rate of 6% and redemption value c. Bond Y has an annual coupon rate of 5% and redemption value c + 50. The price of Bond X exceeds the price of Bond Y by 969.52.
Calculate n.
- 14
- 17
- 23
- 34
- 46
ABy Admin
Nov 19'23
Solution: B
Let X be the price of Bond X. Then, for the two bonds:
[[math]]
\begin{array}{l}{{X=10,000(0.03)a_{\overline{{{2n}}}|0.035}+c(1.035)^{-2n}}}\\ {{X-969.52=10,000(0.025)a_{\overline{{{2n}}}|0.035}+(c+50)(1.035)^{-2n}}}\end{array}
[[/math]]
Subtracting the second equation from the first gives
[[math]]
\begin{array}{l}{{969.52=50a_{\overline{{{2n}}}|0.035}-50(1.035)^{-2n}}}\\ {{969.52=\frac{50}{0.035}[1-(1.035)^{-2n}]-50(1.035)^{-2n}}}\\
{{1.035^{-2n}=459.05/1478.57=0.310469}}\\ {{m=-(0.5)\ln(0.310469)/\vert\ln(1.035)=17.}}
\end{array}
[[/math]]