Revision as of 19:30, 19 November 2023 by Admin (Created page with "'''Solution: E''' <math display = "block"> \begin{array}{l}{{P=C+(F r-C i)a_{\overline{n}|}}}\\ {{962.92=C+(0.04C-0.05C)a_{\overline{20} |0.05}}}\\ {{962.92=C+(-0.01C)12.46221}}\\ {{C=1100}}\end{array} </math> The discount is 1100 – 962.92 = 137.08 {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: E
[[math]]
\begin{array}{l}{{P=C+(F r-C i)a_{\overline{n}|}}}\\ {{962.92=C+(0.04C-0.05C)a_{\overline{20} |0.05}}}\\ {{962.92=C+(-0.01C)12.46221}}\\ {{C=1100}}\end{array}
[[/math]]
The discount is 1100 – 962.92 = 137.08
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.