Revision as of 21:58, 19 November 2023 by Admin (Created page with "'''Solution: E''' <math display = "block"> \begin{array}{l}{{P_{x}=F r a_{\overline{40}|}+Cv^{40}=75a_{\overline{40}|}+Cv^{40}}}\\ {{P_{y}=P_{X}-257.18=60a_{\overline{40}|}+(C+K)v^{40}}}\\ {{P_{x}-P_{y}-257.18=15a_{\overline{40}|}-Kv^{40}}} \\ {{Kv^{40}=15a_{\overline{40}|}-257.18}}\\ {{K(0.2525772)=320.33-257.18}}\\ {{K=250.01}} \end{array} </math> {{soacopyright | 2023 }}")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Exercise


ABy Admin
Nov 19'23

Answer

Solution: E

[[math]] \begin{array}{l}{{P_{x}=F r a_{\overline{40}|}+Cv^{40}=75a_{\overline{40}|}+Cv^{40}}}\\ {{P_{y}=P_{X}-257.18=60a_{\overline{40}|}+(C+K)v^{40}}}\\ {{P_{x}-P_{y}-257.18=15a_{\overline{40}|}-Kv^{40}}} \\ {{Kv^{40}=15a_{\overline{40}|}-257.18}}\\ {{K(0.2525772)=320.33-257.18}}\\ {{K=250.01}} \end{array} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

00