Revision as of 22:22, 19 November 2023 by Admin (Created page with "'''Solution: B''' <math display = "block"> 900=1000 r a_{\overline{40} \mid 0.05}+900 v^{40} </math> Using BA II Plus: <math display = "block"> \begin{aligned} & 1000 r=45 \\ & P=45 a_{\overline{20} \mid 0.04}+900 v^{20} \\ & P=1022.31 \\ & 1022.31=F r a_{\overline{20} \mid 0.04}+1100 v^{20} \\ & F r=38.28 \end{aligned} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: B
[[math]]
900=1000 r a_{\overline{40} \mid 0.05}+900 v^{40}
[[/math]]
Using BA II Plus:
[[math]]
\begin{aligned}
& 1000 r=45 \\
& P=45 a_{\overline{20} \mid 0.04}+900 v^{20} \\
& P=1022.31 \\
& 1022.31=F r a_{\overline{20} \mid 0.04}+1100 v^{20} \\
& F r=38.28
\end{aligned}
[[/math]]