Revision as of 01:30, 20 November 2023 by Admin (Created page with "'''Solution: D''' Equate net present values: <math display = "block"> \begin{array}{c}{{-4000+2000\nu+4000\nu^{2}=2000+4000\nu-X\nu^{2}}}\\ {{\frac{4000+X}{1.1}=6000+\frac{2000}{1.1}}} \\ X= 5460. \end{array} </math> {{soacopyright | 2023 }}")
Exercise
Nov 20'23
Answer
Solution: D
Equate net present values:
[[math]]
\begin{array}{c}{{-4000+2000\nu+4000\nu^{2}=2000+4000\nu-X\nu^{2}}}\\ {{\frac{4000+X}{1.1}=6000+\frac{2000}{1.1}}} \\
X= 5460.
\end{array}
[[/math]]
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