Revision as of 14:49, 20 November 2023 by Admin (Created page with "'''Solution: B''' <math display = "block"> \textrm{PV} = {\frac{10}{1.04}}+{\frac{12}{\left(1.045\right)^{2}}}\,+\,{\frac{15}{\left(1.055\right)^{3}}}\,+\,{\frac{20}{\left(1.07\right)^{4}}}\,=9.615+10.989+12.774+15.258=48.64 </math> {{soacopyright | 2023 }}")
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Exercise


Nov 20'23

Answer

Solution: B

[[math]] \textrm{PV} = {\frac{10}{1.04}}+{\frac{12}{\left(1.045\right)^{2}}}\,+\,{\frac{15}{\left(1.055\right)^{3}}}\,+\,{\frac{20}{\left(1.07\right)^{4}}}\,=9.615+10.989+12.774+15.258=48.64 [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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