Revision as of 18:24, 20 November 2023 by Admin (Created page with "Three asset-liability cash flows are given in the following table where a positive amount is an asset cash flow and a negative amount is a liability due at the corresponding time {| class="table" ! t (in years) !! 0 !! 1 !! 2 !! 3 |- | X || 102,400 || −192,000 || 0 || 100,000 |- | Y || 158,400|| −342,000 || 100,000 || 100,000 |- | Z || −89,600 || 288,000 || 100,000 || -300,000 |} Determine which set of cash flows is Redington immunized for an annual effective int...")
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Nov 20'23

Exercise

Three asset-liability cash flows are given in the following table where a positive amount is an asset cash flow and a negative amount is a liability due at the corresponding time

t (in years) 0 1 2 3
X 102,400 −192,000 0 100,000
Y 158,400 −342,000 100,000 100,000
Z −89,600 288,000 100,000 -300,000

Determine which set of cash flows is Redington immunized for an annual effective interest rate of i = 25%.

  • X only
  • Y only
  • Z only
  • X, Y, and Z
  • The correct answer is not given by (A), (B), (C) or (D)

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

Nov 20'23

Solution: A

Let [math]h(i)[/math] be the present value of the cash flows. For Redington immunization, the value of the function and its first derivative at [math]25 \%[/math] must be zero and the second derivative must be positive. [math]\mathrm{X}[/math] is immunized because:

[[math]] \begin{aligned} & h(0.25)=102,400-192,000 / 1.25+100,000 / 1.25^3=0 \\ & h^{\prime}(0.25)=192,000 / 1.25^2-100,000(3) / 1.25^4=0 \\ & h^{\prime \prime}(0.25)=-192,000(2) / 1.25^3+100,000(3)(4) / 1.25^5=196,608\gt0 \end{aligned} [[/math]]

[math]\mathrm{Y}[/math] is not immunized because:

[[math]] \begin{aligned} & h(0.25)=158,400-342,000 / 1.25+100,000 / 1.25^2+100,000 / 1.25^3=0 \\ & h^{\prime}(0.25)=342,000 / 1.25^2-100,000(2) / 1.25^3-100,000(3) / 1.25^4=-6,400 \neq 0 \end{aligned} [[/math]]

[math]\mathrm{Z}[/math] is not immunized because

[[math]] h(0.25)=-89,600+288,000 / 1.25+100,000 / 1.25^2-300,000 / 1.25^3=51,200 \neq 0 [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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