Revision as of 21:28, 20 November 2023 by Admin (Created page with "'''Solution: C''' Let <math>x</math> and <math>y</math> be the amount invested in the five and twenty year bonds respectively. To match the present values: <math>x+y=500,000 e^{-0.07(10)}+500,000 e^{-0.07(15)}=423,262</math>. To match the durations, noting that the denominators of the durations for assets and liabilities are the same, <math>5 x+20 y=500,000(10) e^{-0.07(10)}+500,000(15) e^{-0.07(15)}=5,107,460</math>. Subtracting five times the first equation from the s...")
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Exercise


Nov 20'23

Answer

Solution: C

Let [math]x[/math] and [math]y[/math] be the amount invested in the five and twenty year bonds respectively. To match the present values: [math]x+y=500,000 e^{-0.07(10)}+500,000 e^{-0.07(15)}=423,262[/math]. To match the durations, noting that the denominators of the durations for assets and liabilities are the same, [math]5 x+20 y=500,000(10) e^{-0.07(10)}+500,000(15) e^{-0.07(15)}=5,107,460[/math]. Subtracting five times the first equation from the second one gives [math]15 y=2,991,150[/math] for [math]y=199,410[/math] and [math]x=423,262-[/math] [math]199,410=223,852[/math].

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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