Revision as of 21:40, 20 November 2023 by Admin (Created page with "'''Solution: E''' Let x be the amount invested in Bond A and y the amount invested in Bond B. Then 2y is invested in Bond C. To match the present value of the assets and liabilities: <math display = "block"> \begin{array}{l}{{x+y+2y=190,000(1.07)^{-20.5}}}\\ {{x+3y=47,466.39.}}\end{array} </math> To match the Macauley durations, . Then, <math display = "block"> \begin{array}{c}{{20.5(47,466.39)=10(47,466.39-3y)+75y}}\\ {{\phantom{M}}}\\ {{y=\frac{20.5(47,366.39)-10(...")
Exercise
Nov 20'23
Answer
Solution: E
Let x be the amount invested in Bond A and y the amount invested in Bond B. Then 2y is invested in Bond C. To match the present value of the assets and liabilities:
[[math]]
\begin{array}{l}{{x+y+2y=190,000(1.07)^{-20.5}}}\\ {{x+3y=47,466.39.}}\end{array}
[[/math]]
To match the Macauley durations, . Then,
[[math]]
\begin{array}{c}{{20.5(47,466.39)=10(47,466.39-3y)+75y}}\\ {{\phantom{M}}}\\ {{y=\frac{20.5(47,366.39)-10(47,466.39)}{75-30}=11,075.49}}\end{array}
[[/math]]
and
[[math]]X = 47,466.39 – 3(11,075.49) = 14,239.92[[/math]]