Revision as of 10:18, 22 November 2023 by Admin (Created page with "'''Solution: A''' Initial deposit = 140, Withdrawal on June 1: W Final Amount= 100 Dollar-Weighted= 15% Time-Weighted= 11% Dollar-Weighted: <math display = "block"> \begin{aligned} 140(1.15) – W[1+7/12*.15]=100 \\ W[1+7/12*.15]=61 \\ W= 56.09 \end{aligned} </math> Time-Weighted: <math display = "block"> \begin{aligned} (X/140)(85/(X-56.09))-1=.11 \\ X= 123.81 \end{aligned} </math> {{cite web |url=https://digitalcommons.calpoly.edu/cgi/viewcontent.cgi?article=1...")
Exercise
ABy Admin
Nov 22'23
Answer
Solution: A
Initial deposit = 140, Withdrawal on June 1: W
Final Amount= 100
Dollar-Weighted= 15%
Time-Weighted= 11%
Dollar-Weighted:
[[math]]
\begin{aligned}
140(1.15) – W[1+7/12*.15]=100 \\
W[1+7/12*.15]=61 \\
W= 56.09
\end{aligned}
[[/math]]
Time-Weighted:
[[math]]
\begin{aligned}
(X/140)(85/(X-56.09))-1=.11 \\
X= 123.81
\end{aligned}
[[/math]]
Hardiek, Aaron (June 2010). "Study Questions for Actuarial Exam 2/FM". digitalcommons.calpoly.edu. Retrieved November 20, 2023.