Revision as of 23:50, 25 November 2023 by Admin (Created page with "'''Solution: A''' <math display = "block"> (1+i)=\left(1+i^{(12)} / 12\right)^{12}</math> so <math display = "block">i^{(12)}=12\left[(1+i)^{1 / 12}-1\right]=12\left[(1.4295)^{1 / 12}-1\right]=.3627 </math> '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}")
Exercise
ABy Admin
Nov 25'23
Answer
Solution: A
[[math]]
(1+i)=\left(1+i^{(12)} / 12\right)^{12}[[/math]]
so
[[math]]i^{(12)}=12\left[(1+i)^{1 / 12}-1\right]=12\left[(1.4295)^{1 / 12}-1\right]=.3627
[[/math]]
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.