Revision as of 14:04, 26 November 2023 by Admin (Created page with "'''Solution: C''' <math display="block"> 368.21=178.66(1+3 i)^{10} \text { so } 1+3 i=(368.21 / 178.66)^{\cdot 1}=1.074996 </math> Thus <math>i=.074996 / 3=.024999</math>. Value after 8 years is <math>\left.100(1+i)^3(1+3 i)^5=100(1.024999)^3\right)(1.074996)^5=154.60</math>. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theo...")
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Exercise


ABy Admin
Nov 26'23

Answer

Solution: C

[[math]] 368.21=178.66(1+3 i)^{10} \text { so } 1+3 i=(368.21 / 178.66)^{\cdot 1}=1.074996 [[/math]]

Thus [math]i=.074996 / 3=.024999[/math]. Value after 8 years is [math]\left.100(1+i)^3(1+3 i)^5=100(1.024999)^3\right)(1.074996)^5=154.60[/math].

References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023. Thus [math]i=.074996 / 3=.024999[/math]. Value after 8 years is [math]\left.100(1+i)^3(1+3 i)^5=100(1.024999)^3\right)(1.074996)^5=154.60[/math].

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