Revision as of 17:38, 26 November 2023 by Admin (Created page with "'''Solution: C''' <math display="block"> \frac{10}{(1-d / 4)^{40}}\left(1+\frac{.06}{2}\right)^{40}+20\left(1+\frac{.06}{2}\right)^{30}=100 </math> Solve for <math>d</math> to get <math>d=0.04531789</math> or <math>4.53 \%</math>. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}")
Exercise
ABy Admin
Nov 26'23
Answer
Solution: C
[[math]]
\frac{10}{(1-d / 4)^{40}}\left(1+\frac{.06}{2}\right)^{40}+20\left(1+\frac{.06}{2}\right)^{30}=100
[[/math]]
Solve for [math]d[/math] to get [math]d=0.04531789[/math] or [math]4.53 \%[/math].
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.