Revision as of 21:41, 29 November 2023 by Admin (Created page with "Maxine invests 1000 at the end of each year for 5 years at an effective rate of .10 per year, with interest payable annually. She reinvests the interest each year at rate .08 per year. Find the accumulated value at the end of 5 years. <ul class="mw-excansopts"> <li>5867</li> <li>6000</li> <li>6084</li> <li>6105</li> <li>6150</li> </ul> '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwind...")
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Nov 29'23

Exercise

Maxine invests 1000 at the end of each year for 5 years at an effective rate of .10 per year, with interest payable annually. She reinvests the interest each year at rate .08 per year.

Find the accumulated value at the end of 5 years.

  • 5867
  • 6000
  • 6084
  • 6105
  • 6150

References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.

Nov 29'23

Solution: C

The time diagram is

Time 0 1 2 3 4 5
Deposit 1000 1000 1000 1000 1000
CumDeposit 1000 2000 3000 4000 5000
Interest 100 200 300 400

Hence the accumulated amount is

[[math]] 5000+100(I s)_{\overline{4} \mid .08}=5000+100 \frac{\ddot{s}_{\overline{4} \mid .08}-4}{.08}=5000+100 \frac{4.866601-4}{.08}=6083.25 [[/math]]

References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.

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