Revision as of 20:03, 4 December 2023 by Admin
Exercise
Dec 04'23
Answer
Solution: D
Year 1: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^1=9.7364[/math]
Year 2: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^2=9.4797[/math]
Year 3: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^3=9.2298[/math]
PV: 9.7364+9.4797+9.2298= $28.4458 million.
References
Lo, Andrew W.; Wang, Jiang. "MIT Sloan Finance Problems and Solutions Collection Finance Theory I" (PDF). alo.mit.edu. Retrieved November 30, 2023.