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Exercise


Dec 04'23

Answer

Solution: D

Year 1: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^1=9.7364[/math]

Year 2: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^2=9.4797[/math]

Year 3: [math]10 \times\left(\frac{1.05 \times 1.02}{1.10}\right)^3=9.2298[/math]

PV: 9.7364+9.4797+9.2298= $28.4458 million.

References

Lo, Andrew W.; Wang, Jiang. "MIT Sloan Finance Problems and Solutions Collection Finance Theory I" (PDF). alo.mit.edu. Retrieved November 30, 2023.

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