Revision as of 20:30, 4 December 2023 by Admin (Created page with "'''Solution: B''' Let the annual payment <math>=C</math>. The PV of all my payments, discounted at the dealer's rate, must equal to the price, i.e., <math display="block"> \begin{aligned} & 3500+\frac{C}{0.02}\left(1-\frac{1}{1.02^5}\right)=30000 \\ & 3500+4.71346 C=30000 \\ & C=\$ 5,622.20 \end{aligned} </math> Since I can save at a higher rate, the cost of the financing plan in (a) is only 3500 + C/0.05 (1 − 11.05<sup>5</sup> ) = $27, 841.17. The cost of the sec...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Exercise


ABy Admin
Dec 04'23

Answer

Solution: B

Let the annual payment [math]=C[/math]. The PV of all my payments, discounted at the dealer's rate, must equal to the price, i.e.,

[[math]] \begin{aligned} & 3500+\frac{C}{0.02}\left(1-\frac{1}{1.02^5}\right)=30000 \\ & 3500+4.71346 C=30000 \\ & C=\$ 5,622.20 \end{aligned} [[/math]]

Since I can save at a higher rate, the cost of the financing plan in (a) is only 3500 + C/0.05 (1 − 11.055 ) = $27, 841.17.

The cost of the second option is 30, 000 − 2, 500 = $27, 500. I should pay cash.

References

Lo, Andrew W.; Wang, Jiang. "MIT Sloan Finance Problems and Solutions Collection Finance Theory I" (PDF). alo.mit.edu. Retrieved November 30, 2023.

00