Revision as of 02:18, 16 January 2024 by Admin (Created page with "'''Answer: B''' <math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math>")
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Exercise


Jan 16'24

Answer

Answer: B

[math]{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298[/math]

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