Revision as of 22:22, 17 January 2024 by Admin (Created page with "'''Answer: D''' <math>\hat{S}(1)=0.8</math> <math>\operatorname{Var}[S(1)]=\frac{S(1)(1-S(1)}{n} \approx \frac{(0.8)(0.2)}{1000}=0.01265^{2}</math> <math>\Rightarrow 95 \% \mathrm{CI}</math> is approximately <math>(0.8 \pm 1.96(0.01265))=(0.775,0.825)</math>")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Exercise

AAdmin
Jan 17'24

Answer

Answer: D

[math]\hat{S}(1)=0.8[/math]

[math]\operatorname{Var}[S(1)]=\frac{S(1)(1-S(1)}{n} \approx \frac{(0.8)(0.2)}{1000}=0.01265^{2}[/math]

[math]\Rightarrow 95 \% \mathrm{CI}[/math] is approximately [math](0.8 \pm 1.96(0.01265))=(0.775,0.825)[/math]

00