Revision as of 11:39, 18 January 2024 by Admin (Created page with "'''Answer: C''' The earlier the death (before year 30), the larger the loss. Since we are looking for the <math>95^{\text {th }}</math> percentile of the present value of benefits random variable, we must find the time at which <math>5 \%</math> of the insureds have died. The present value of the death benefit for that insured is what is being asked for. <math display="block"> \begin{aligned} & l_{45}=99,033.9 \Rightarrow 0.95 l_{45}=94,082.2 \\ & l_{65}=94,579.7 \\ &...")
Exercise
Jan 18'24
Answer
Answer: C
The earlier the death (before year 30), the larger the loss. Since we are looking for the [math]95^{\text {th }}[/math] percentile of the present value of benefits random variable, we must find the time at which [math]5 \%[/math] of the insureds have died. The present value of the death benefit for that insured is what is being asked for.
[[math]]
\begin{aligned}
& l_{45}=99,033.9 \Rightarrow 0.95 l_{45}=94,082.2 \\
& l_{65}=94,579.7 \\
& l_{66}=94,020.3
\end{aligned}
[[/math]]
So, the time is between ages 65 and 66, i.e., time 20 and time 21.
[[math]]
\begin{aligned}
& l_{65}-l_{66}=94,579.7-94,020.3=559.4 \\
& l_{65+t}-l_{66}=94,579.7-94,082.2=497.5
\end{aligned}
[[/math]]
[math]497.5 / 559.4=0.8893[/math]
The time just before the last [math]5 \%[/math] of deaths is expected to occur is: [math]20+0.8893=20.8893[/math]
The present value of death benefits at this time is:
[math]100,000 e^{-20.8893(0.05)}=35,188[/math]