Revision as of 11:48, 18 January 2024 by Admin (Created page with "'''Answer: B''' <math>\operatorname{Var}(Z)=0.10 E[Z] \Rightarrow v^{50}{ }_{25} p_{x}\left(1-{ }_{25} p_{x}\right)=0.10 \cdot v^{25}{ }_{25} p_{x}</math> <math>\Rightarrow \frac{(1-0.57)}{(1+i)^{50}}=0.10 \times \frac{1}{(1+i)^{25}}</math> <math>\Rightarrow(1+i)^{25}=\frac{0.43}{0.10}=4.3 \Rightarrow i=0.06</math> {{soacopyright|2024}}")
Exercise
Jan 18'24
Answer
Answer: B
[math]\operatorname{Var}(Z)=0.10 E[Z] \Rightarrow v^{50}{ }_{25} p_{x}\left(1-{ }_{25} p_{x}\right)=0.10 \cdot v^{25}{ }_{25} p_{x}[/math]
[math]\Rightarrow \frac{(1-0.57)}{(1+i)^{50}}=0.10 \times \frac{1}{(1+i)^{25}}[/math]
[math]\Rightarrow(1+i)^{25}=\frac{0.43}{0.10}=4.3 \Rightarrow i=0.06[/math]