Revision as of 23:23, 18 January 2024 by Admin (Created page with "'''Answer: C''' <math>(\bar{I} \bar{a})_{40: t}=\int_{0}^{t} s_{s} p_{40} v^{s} d s \Rightarrow \frac{d(\overline{I \bar{a}})_{40: \nexists}}{d t}=t_{t} p_{40} v^{t}</math> At <math>t=10.5</math>, <math>10.5_{10.5} E_{40}=10.5_{10} p_{400.5} p_{50} v^{10.5}</math> <math>=10.5_{10} E_{400.5} p_{50} v^{0.5}</math> <math>=10.5 \times 0.60920 \times(1-0.5 \times 0.001209)(0.975900073)</math> <math>=6.239</math> {{soacopyright|2024}}")
Exercise
Jan 18'24
Answer
Answer: C
[math](\bar{I} \bar{a})_{40: t}=\int_{0}^{t} s_{s} p_{40} v^{s} d s \Rightarrow \frac{d(\overline{I \bar{a}})_{40: \nexists}}{d t}=t_{t} p_{40} v^{t}[/math]
At [math]t=10.5[/math],
[math]10.5_{10.5} E_{40}=10.5_{10} p_{400.5} p_{50} v^{10.5}[/math]
[math]=10.5_{10} E_{400.5} p_{50} v^{0.5}[/math]
[math]=10.5 \times 0.60920 \times(1-0.5 \times 0.001209)(0.975900073)[/math]
[math]=6.239[/math]
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