Revision as of 20:52, 19 January 2024 by Admin (Created page with "'''Answer: A''' <math>P_{30: 20 \mid}=\frac{1}{\ddot{a}_{30: \overline{20}}}-d \Rightarrow \frac{2,143}{100,000}+0.05=\frac{1}{\ddot{a}_{30: \overline{20}}} \Rightarrow \ddot{a}_{30: 20}=14</math> <math>A_{30: \overline{20}}=1-d \ddot{a}_{30: \overline{20}}=1-0.05(14)=0.3</math> <math>G \ddot{a}_{30: \overline{20}}=100,000 A_{30: \overline{20}}+\left(200+50 \ddot{a}_{30: \overline{20}}\right)+\left(0.33 G+0.06 G \ddot{a}_{30: \overline{20}}\right)</math> <math>14 G=1...")
Exercise
ABy Admin
Jan 19'24
Answer
Answer: A
[math]P_{30: 20 \mid}=\frac{1}{\ddot{a}_{30: \overline{20}}}-d \Rightarrow \frac{2,143}{100,000}+0.05=\frac{1}{\ddot{a}_{30: \overline{20}}} \Rightarrow \ddot{a}_{30: 20}=14[/math]
[math]A_{30: \overline{20}}=1-d \ddot{a}_{30: \overline{20}}=1-0.05(14)=0.3[/math]
[math]G \ddot{a}_{30: \overline{20}}=100,000 A_{30: \overline{20}}+\left(200+50 \ddot{a}_{30: \overline{20}}\right)+\left(0.33 G+0.06 G \ddot{a}_{30: \overline{20}}\right)[/math]
[math]14 G=100,000(0.3)+[200+50(14)]+(0.33 G+0.84 G)[/math]
[math]12.83 G=30,900[/math]
[math]G=2408[/math]
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