Revision as of 21:10, 19 January 2024 by Admin (Created page with "'''Answer: C''' Let the monthly net premium <math>=\pi</math> <math display="block"> \begin{aligned} & 12 \pi=\frac{100,000 \bar{A}_{45}}{\ddot{a}_{45: 20}^{(12)}} \\ & \alpha(12)=1.00020 \\ & \beta(12)=0.46651 \\ & \frac{i}{\delta}=1.02480 \\ & 100,000 \bar{A}_{45}=100,000 \frac{i}{\delta} A_{45}=(1.02480)(15,161)=15,536.99 \\ & \ddot{a}_{45: 20}^{(12)}=\alpha(12) \ddot{a}_{45: 20}-\beta(12)\left(1-{ }_{20} E_{45}\right) \\ & =1.00020[12.9391]-0.46651(1-0.35994) \\ &...")
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Exercise


ABy Admin
Jan 19'24

Answer

Answer: C

Let the monthly net premium [math]=\pi[/math]

[[math]] \begin{aligned} & 12 \pi=\frac{100,000 \bar{A}_{45}}{\ddot{a}_{45: 20}^{(12)}} \\ & \alpha(12)=1.00020 \\ & \beta(12)=0.46651 \\ & \frac{i}{\delta}=1.02480 \\ & 100,000 \bar{A}_{45}=100,000 \frac{i}{\delta} A_{45}=(1.02480)(15,161)=15,536.99 \\ & \ddot{a}_{45: 20}^{(12)}=\alpha(12) \ddot{a}_{45: 20}-\beta(12)\left(1-{ }_{20} E_{45}\right) \\ & =1.00020[12.9391]-0.46651(1-0.35994) \\ & =12.6431 \\ & 12 \pi=\frac{15,536.99}{12.6431} \\ & 12 \pi=1228.891 \\ & \pi=102.41 \end{aligned} [[/math]]

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