Revision as of 23:24, 19 January 2024 by Admin (Created page with "'''Answer: C''' <math display="block"> \begin{aligned} & G \ddot{a}_{40: 20}^{(12)}=100,000\left(\frac{i}{\delta}\right) A_{40}+200+0.04 G \ddot{a}_{40: 20}^{(12)} \\ & \ddot{a}_{40: 20}^{(12)}=\alpha(12) \ddot{a}_{40: 20}-\left(1-{ }_{20} E_{40}\right) \beta(12) \\ & \quad=1.00020 \cdot 12.9935-(1-0.36663) \cdot 0.46651=12.700625 \\ & G=\frac{(100,000)(1.02480)(0.12106)+200}{0.96 \times 12.700625}=1033.92 \\ & \Rightarrow \mathrm{G} / 12=86.16 \end{aligned} </math>...")
Exercise
ABy Admin
Jan 19'24
Answer
Answer: C
[[math]]
\begin{aligned}
& G \ddot{a}_{40: 20}^{(12)}=100,000\left(\frac{i}{\delta}\right) A_{40}+200+0.04 G \ddot{a}_{40: 20}^{(12)} \\
& \ddot{a}_{40: 20}^{(12)}=\alpha(12) \ddot{a}_{40: 20}-\left(1-{ }_{20} E_{40}\right) \beta(12) \\
& \quad=1.00020 \cdot 12.9935-(1-0.36663) \cdot 0.46651=12.700625 \\
& G=\frac{(100,000)(1.02480)(0.12106)+200}{0.96 \times 12.700625}=1033.92 \\
& \Rightarrow \mathrm{G} / 12=86.16
\end{aligned}
[[/math]]