Revision as of 01:10, 20 January 2024 by Admin (Created page with "For a fully discrete whole life insurance of 10,000 on <math>(x)</math>, you are given: (i) Deaths are uniformly distributed over each year of age (ii) The net premium is 647.46 (iii) The net premium policy value at the end of year 4 is 1405.08 (iv) <math>q_{x+4}=0.04561</math> (v) <math>\quad i=0.03</math> Calculate the net premium policy value at the end of 4.5 years. <ul class="mw-excansopts"><li> 1570</li><li> 1680</li><li> 1750</li><li> 1830</li><li> 1900</li...")
ABy Admin
Jan 20'24
Exercise
For a fully discrete whole life insurance of 10,000 on [math](x)[/math], you are given:
(i) Deaths are uniformly distributed over each year of age
(ii) The net premium is 647.46
(iii) The net premium policy value at the end of year 4 is 1405.08
(iv) [math]q_{x+4}=0.04561[/math]
(v) [math]\quad i=0.03[/math]
Calculate the net premium policy value at the end of 4.5 years.
- 1570
- 1680
- 1750
- 1830
- 1900
ABy Admin
Jan 20'24
Answer: E
[[math]]
\begin{aligned}
{ }_{4.5} V & =v_{0.5}^{0.5} p_{x+4.5} V+v_{0.5}^{0.5} q_{x+4.5} b, \text { where } b=10,000 \text { is the death benefit during year } 5 \\
{ }_{0.5} q_{x+4.5} & =\frac{{ }_{0.5} q_{x+4}}{1-{ }_{0.5} q_{x+4}}=\frac{0.5(0.04561)}{1-0.5(0.04561)}=0.02334 \\
{ }_{0.5} p_{x+4.5} & =0.97666 \\
{ }_{5} V & =\frac{\left({ }_{4} V+P\right)(1.03)-q_{x+4} b}{p_{x+4}} \\
{ }_{5} V & =\frac{(1,405.08+647.46)(1.03)-0.04561(10,000)}{0.95439}=1,737.25 \\
{ }_{4.5} V & =(1.03)^{-0.5}(0.97666)(1,737.25)+(1.03)^{-0.5}(0.02334)(10,000) \\
& =1,671.81+229.98=1,902
\end{aligned}
[[/math]]
[math]{ }_{4.5} V[/math] can also be calculated recursively:
[[math]]
{ }_{0.5} q_{x+4}=0.5(0.04561)=0.02281
[[/math]]
[math]{ }_{4.5} V=\frac{(1,405.08+647.16)(1.03)^{0.5}-0.02281(10,000) /(1.03)^{0.5}}{1-0.02281}=1,902[/math]
The interest adjustment on the death benefit term is needed because the death benefit will not be paid for another one-half year.