Revision as of 02:41, 20 January 2024 by Admin (Created page with "'''Answer: C''' <math>{ }_{0} V=0</math> <math>{ }_{2} V=2000</math> Year 1: <math>\quad\left({ }_{0} V+P\right)(1+i)=q_{x}\left(2000+{ }_{1} V\right)+p_{x 1} V</math> <math display = "block"> P(1.1)=0.15\left(2000+{ }_{1} V\right)+0.85\left({ }_{1} V\right) </math> <math display = "block"> 1.1 P-300={ }_{1} V </math> Year 2: <math>\quad\left({ }_{1} V+P\right)(1+i)=q_{x+1}\left(2000+{ }_{2} V\right)+p_{x+1}(2000)</math> <math display = "block"> \begin{aligne...")
Exercise
ABy Admin
Jan 20'24
Answer
Answer: C
[math]{ }_{0} V=0[/math]
[math]{ }_{2} V=2000[/math]
Year 1: [math]\quad\left({ }_{0} V+P\right)(1+i)=q_{x}\left(2000+{ }_{1} V\right)+p_{x 1} V[/math]
[[math]]
P(1.1)=0.15\left(2000+{ }_{1} V\right)+0.85\left({ }_{1} V\right)
[[/math]]
[[math]]
1.1 P-300={ }_{1} V
[[/math]]
Year 2: [math]\quad\left({ }_{1} V+P\right)(1+i)=q_{x+1}\left(2000+{ }_{2} V\right)+p_{x+1}(2000)[/math]
[[math]]
\begin{aligned}
& (1.1 P-300+P)(1.1)=0.165(2000+2000)+0.835(2000) \\
& 2.31 P-330=2330 \\
& P=\frac{2330+330}{2.31}=1152
\end{aligned}
[[/math]]