Revision as of 02:53, 20 January 2024 by Admin (Created page with "'''Answer: D''' <math <math display="block"> \begin{aligned} & \ddot{a}_{x+10}=\left(1-A_{x+10}\right) / d=(1-0.4) /(0.05 / 1.05)=12.6 \\ & \ddot{a}_{x+10}^{(12)} \approx 12.6-11 / 24=12.142 \\ & { }_{10} V=10,000 A_{x+10}+100 \ddot{a}_{x+10}-12 \ddot{a}_{x+10}^{(12)}(30)(1-0.05) \\ & { }_{10} V=10,000(0.4)+100(12.6)-12(12.142)(28.50) \\ & { }_{10} V=1107 \end{aligned} </math> {{soacopyright|2024}}")
Exercise
ABy Admin
Jan 20'24
Answer
Answer: D
[[math]]
\begin{aligned}
& \ddot{a}_{x+10}=\left(1-A_{x+10}\right) / d=(1-0.4) /(0.05 / 1.05)=12.6 \\
& \ddot{a}_{x+10}^{(12)} \approx 12.6-11 / 24=12.142 \\
& { }_{10} V=10,000 A_{x+10}+100 \ddot{a}_{x+10}-12 \ddot{a}_{x+10}^{(12)}(30)(1-0.05) \\
& { }_{10} V=10,000(0.4)+100(12.6)-12(12.142)(28.50) \\
& { }_{10} V=1107
\end{aligned}
[[/math]]