Revision as of 03:00, 20 January 2024 by Admin (Created page with "'''Answer: B''' <math>L=10,000 v^{K_{45}+1}-P \ddot{a}_{\overline{K_{45}+1 \mid}}=10,000 v^{11}-P \ddot{a}_{\overline{11}}</math> <math>4450=10,000(0.58468)-8.7217 P</math> <math>P=(5,846.8-4,450) / 8.7217=160.15</math> <math>A_{55}=1-d \ddot{a}_{55}=1-(0.05 / 1.05)(13.4205)=0.36093</math> <math>{ }_{10} V=10,000 A_{55}-P \ddot{a}_{55}=(10,000)(0.36093)-(160.15)(13.4205)=1,460</math> {{soacopyright|2024}}")
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Exercise


ABy Admin
Jan 20'24

Answer

Answer: B

[math]L=10,000 v^{K_{45}+1}-P \ddot{a}_{\overline{K_{45}+1 \mid}}=10,000 v^{11}-P \ddot{a}_{\overline{11}}[/math]

[math]4450=10,000(0.58468)-8.7217 P[/math]

[math]P=(5,846.8-4,450) / 8.7217=160.15[/math]

[math]A_{55}=1-d \ddot{a}_{55}=1-(0.05 / 1.05)(13.4205)=0.36093[/math]

[math]{ }_{10} V=10,000 A_{55}-P \ddot{a}_{55}=(10,000)(0.36093)-(160.15)(13.4205)=1,460[/math]

Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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