Revision as of 21:14, 13 May 2024 by Admin (Created page with "One possible solution: <syntaxhighlight lang="C"> void right_side_up(int n) { int x,y; for (y= 1; y <= n; y++) { for (x= 0; x < n-y; x++) putchar(' '); for (x= (n-y); x < (n-y)+(2*y-1); x++) putchar('*'); putchar('\n'); } } </syntaxhighlight> Another solution: <syntaxhighlight lang="C"> #include<stdio.h> int main(void) { int n; scanf("%d",&n); for(int i=0;i<n;i++) { for(int j=0;j<n-i-1;j++)...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Exercise


May 13'24

Answer

One possible solution: void right_side_up(int n) {

   int x,y;
   for (y= 1; y <= n; y++)
   {
       for (x= 0; x < n-y; x++)
           putchar(' ');
       for (x= (n-y); x < (n-y)+(2*y-1); x++)
           putchar('*');
       putchar('\n');
   }

}

Another solution:

#include

int main(void) {

 int n;
 scanf("%d",&n);
 for(int i=0;i

}

00