Revision as of 03:27, 9 June 2024 by Bot (Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> (Chebyshev<ref group="Notes" >P. L. Chebyshev, “On Mean Values,” ''J.\ Math.\ Pure.\ Appl.,'' vol. 12 (1867), pp. 177--184.</ref>) Assume that <math>X_1</math>, <math>X_2</math>, \dots, <math>X_n</math> are independent random variables with p...")
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Jun 09'24

Exercise

[math] \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}[/math]

(Chebyshev[Notes 1]) Assume

that [math]X_1[/math], [math]X_2[/math], \dots, [math]X_n[/math] are independent random variables with possibly different distributions and let [math]S_n[/math] be their sum. Let [math]m_k = E(X_k)[/math], [math]\sigma_k^2 = V(X_k)[/math], and [math]M_n = m_1 + m_2 +\cdots+ m_n[/math]. Assume that [math]\sigma_k^2 \lt R[/math] for all [math]k[/math]. Prove that, for any [math]\epsilon \gt 0[/math],

[[math]] P\left( \left| \frac {S_n}n - \frac {M_n}n \right| \lt \epsilon \right) \to 1 [[/math]]

as [math]n \rightarrow \infty[/math].

Notes

  1. P. L. Chebyshev, “On Mean Values,” J.\ Math.\ Pure.\ Appl., vol. 12 (1867), pp. 177--184.