May 07'23
Exercise
A store has 80 modems in its inventory, 30 coming from Source A and the remainder from Source B. Of the modems in inventory from Source A, 20% are defective. Of the modems in inventory from Source B, 8% are defective.
Calculate the probability that exactly two out of a sample of five modems selected without replacement from the store’s inventory are defective.
- 0.010
- 0.078
- 0.102
- 0.105
- 0.125
May 07'23
Solution: C
The number of defective modems is 20% x 30 + 8% x 50 = 10.
The probability that exactly two of a random sample of five are defective is
[[math]]
\frac{\binom{10}{2} \binom{70}{3}}{\binom{80}{5}} = 0.102.
[[/math]]