Apr 29'23
Exercise
An insurance company insures red and green cars. An actuary compiles the following data:
Color of Car | Red | Green |
Number insured | 300 | 700 |
Probability an accident occurs | 0.10 | 0.05 |
Probability that the claim exceeds the deductible, given an accident occurs from this group | 0.9 | 0.8 |
The actuary randomly picks a claim from all claims that exceed the deductible. Calculate the probability that the claim is on a red car.
- 0.300
- 0.462
- 0.491
- 0.667
- 0.692
Apr 29'23
Solution: C
Let R be the event the car is red and G be the event the car is green. Let E be the event that the claim exceeds the deductible. Then,
[[math]]
\operatorname{P}(R | E ) = \frac{\operatorname{P}( R) \operatorname{P}( E | R)}{\operatorname{P}( R ) \operatorname{P}( E | R ) + \operatorname{P}(G) \operatorname{P}( E | G)} = \frac{0.3(0.09)}{0.3(0.09) + 0.7(0.04)} = \frac{0.027}{0.055} = 0.491.
[[/math]]
Note that if A is the probability of an accident,
[[math]]
\operatorname{P}( E | R ) = \operatorname{P}( E | R \cap A) \operatorname{P}( A | R ) = 0.1(0.9) = 0.09.
[[/math]]