May 13'23
Exercise
You are given:
Claim Size (X) | Number of Claims |
---|---|
(0,25] | 25 |
(25,50] | 28 |
(50,100] | 15 |
(100,200] | 6 |
Assume a uniform distribution of claim sizes within each interval.
Calculate [math]\operatorname{E}(X^2) - \operatorname{E}( (X \wedge 150)^2 ][/math]
- Less than 200
- At least 200, but less than 300
- At least 300, but less than 400
- At least 400, but less than 500
- At least 500
May 13'23
Key: C
In general,
[[math]]\begin{aligned}
\operatorname{E}(X^{2})-E\left[(X \wedge 150)^{2}\right] &=\int_{0}^{200} x^{2} f(x) d x-\int_{0}^{150} x^{2} f(x) d x-150^{2} \int_{150}^{200} f(x) d x \\
& =\int_{150}^{200}\left(x^{2}-150^{2}\right) f(x) d x
\end{aligned}[[/math]]
Assuming a uniform distribution, the density function over the interval from 100 to 200 is [math]6 / 7400[/math] (the probability of [math]6 / 74[/math] assigned to the interval divided by the width of the interval). The answer is
[[math]]\int_{150}^{200}\left(x^{2}-150^{2}\right) \frac{6}{7400} d x=\left.\left(\frac{x^{3}}{3}-150^{2} x\right) \frac{6}{7400}\right|_{150} ^{200}=337.84[[/math]]