Nov 20'23
Exercise
Three asset-liability cash flows are given in the following table where a positive amount is an asset cash flow and a negative amount is a liability due at the corresponding time
t (in years) | 0 | 1 | 2 | 3 |
---|---|---|---|---|
X | 102,400 | −192,000 | 0 | 100,000 |
Y | 158,400 | −342,000 | 100,000 | 100,000 |
Z | −89,600 | 288,000 | 100,000 | -300,000 |
Determine which set of cash flows is Redington immunized for an annual effective interest rate of i = 25%.
- X only
- Y only
- Z only
- X, Y, and Z
- The correct answer is not given by (A), (B), (C) or (D)
Nov 20'23
Solution: A
Let [math]h(i)[/math] be the present value of the cash flows. For Redington immunization, the value of the function and its first derivative at [math]25 \%[/math] must be zero and the second derivative must be positive. [math]\mathrm{X}[/math] is immunized because:
[[math]]
\begin{aligned}
& h(0.25)=102,400-192,000 / 1.25+100,000 / 1.25^3=0 \\
& h^{\prime}(0.25)=192,000 / 1.25^2-100,000(3) / 1.25^4=0 \\
& h^{\prime \prime}(0.25)=-192,000(2) / 1.25^3+100,000(3)(4) / 1.25^5=196,608\gt0
\end{aligned}
[[/math]]
[math]\mathrm{Y}[/math] is not immunized because:
[[math]]
\begin{aligned}
& h(0.25)=158,400-342,000 / 1.25+100,000 / 1.25^2+100,000 / 1.25^3=0 \\
& h^{\prime}(0.25)=342,000 / 1.25^2-100,000(2) / 1.25^3-100,000(3) / 1.25^4=-6,400 \neq 0
\end{aligned}
[[/math]]
[math]\mathrm{Z}[/math] is not immunized because
[[math]]
h(0.25)=-89,600+288,000 / 1.25+100,000 / 1.25^2-300,000 / 1.25^3=51,200 \neq 0
[[/math]]