BBy Bot
Jun 09'24
Exercise
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A lead change in a random walk occurs at time
[math]2k[/math] if [math]S_{2k-1}[/math] and [math]S_{2k+1}[/math] are of opposite sign.
- Give a rigorous argument which proves that among all walks of length [math]2m[/math] that have an equalization at time [math]2k[/math], exactly half have a lead change at time [math]2k[/math].
- Deduce that the total number of lead changes among all walks of length [math]2m[/math] equals
[[math]] {1\over 2}(g_{2m} - u_{2m})\ . [[/math]]
- Find an asymptotic expression for the average number of lead changes in a random walk of length [math]2m[/math].