May 13'23
Exercise
An individual performs dangerous motorcycle jumps at extreme sports events around the world.
The annual cost of repairs to their motorcycle is modeled by a Pareto distribution with [math]\theta = 5000 [/math] and [math] \alpha = 2 [/math].
An insurance policy reimburses motorcycle repair costs subject to the following provisions:
- The annual ordinary deductible is 1000.
- The policyholder pays 20% of repair costs between 1000 and 6000 each year.
- The policyholder pays 100% of the annual repair costs above 6000 until they have paid 10,000 in out-of-pocket repair costs each year.
- The policyholder pays 10% of the remaining repair costs each year.
Calculate the expected annual insurance reimbursement.
- 2300
- 2500
- 2700
- 2900
- 3100
May 13'23
Key: C
Insurance pays 80% of the portion of annual claim between 6,000 and 1,000, and 90% of the portion of annual claims over 14,000.
The 14,000 breakpoint is where the policyholder has paid 10,000:
1000 = deductible
1000 = 20% of costs between 1000 and 6000
8000 = 100% of costs between 14,000 and 6,000
[[math]]
\operatorname{E}(X \wedge x ) = \theta \left( 1 - \frac{\theta}{x + \theta} \right) = \frac{5000x}{x + 5000}
[[/math]]
[math]x[/math] | [math]\operatorname{E}(X \wedge x ) [/math] |
---|---|
1000 | 833.33 |
6000 | 2727.27 |
14000 | 3684.21 |
[math]\infty[/math] | 5000 |
[[math]]
\begin{aligned}
&0.80[ \operatorname{E}[ X \wedge 6000) − \operatorname{E}[ X \wedge 1000)] + 0.90[ \operatorname{E}[ X ) − \operatorname{E}( X \wedge 14000)] \\
&= 0.80[2727, 27 − 833.33] + 0.90[5000 − 3684.21] \\
&= 1515.15 + 1184.21 = 2699.36
\end{aligned}
[[/math]]