Nov 20'23
Exercise
Nov 20'23
Solution: E
[[math]]
\begin{array}{l}{{(1+s_{3})^{3}=(1+s_{2})^{2}(1+1f_{2})}}\\ {{0.85892={\frac{1}{(1+s_{2})^{3}}},s_{3}=0.052}}\\ {{0.90703=\frac{1}{(1+s_{2})^{2}},s_{2}=0.050
}}\\ {{1.052^{3}=1.050^{2}(1+_1f_{2})
}}\\ {{_1f_{2} = 0.056}}\end{array}
[[/math]]