May 08'23
Exercise
In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, until the fourth damaged package is discovered.
Calculate the probability that exactly 12 packages are inspected.
- 0.079
- 0.119
- 0.237
- 0.243
- 0.358
May 08'23
Solution: B
The requested probability can be determined as P(3 of first 11 damaged) P(12th is damaged | 3 of first 11 damaged)
[[math]]
= \frac{\binom{7}{3} \binom{13}{8}}{\frac{20}{11}} \frac{4}{9} = \frac{351(1287)}{167960} \frac{4}{9} = 0.119.
[[/math]]