May 08'23

Exercise

In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, until the fourth damaged package is discovered.

Calculate the probability that exactly 12 packages are inspected.

  • 0.079
  • 0.119
  • 0.237
  • 0.243
  • 0.358

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 08'23

Solution: B

The requested probability can be determined as P(3 of first 11 damaged) P(12th is damaged | 3 of first 11 damaged)

[[math]] = \frac{\binom{7}{3} \binom{13}{8}}{\frac{20}{11}} \frac{4}{9} = \frac{351(1287)}{167960} \frac{4}{9} = 0.119. [[/math]]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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