Exercise
A company faces the following liabilities at the end of the corresponding years:
Year | 1 | 2 | 3 | 4 |
Liability | 5,766 | X | 15,421 | 7,811 |
The company can invest in the following three annual coupon bonds redeemable at par:
Term (in years) | Annual coupon rate | |
---|---|---|
Bond A | 1 | 1% |
Bond B | 3 | 5% |
Bond C | 4 | 7% |
The company invests in each bond so that the asset and liability cash flows are exactly matched.
Calculate X.
- 1221
- 1245
- 1290
- 1318
- 1375
Solution: A
Let [math]a, b[/math], and [math]c[/math] represent the face values of the three bonds. One, two, three, and four years from now, respectively: the 1-year bond provides payments of [math]1.01 a, 0,0,0[/math]; the 3-year bond provides payments of [math]0.05 \mathrm{~b}, 0.05 \mathrm{~b}, 1.05 \mathrm{~b}, 0[/math]; and the 4-year bond provides payments of [math]0.07 c, 0.07 c, 0.07 c, 1.07 c[/math]. The total payments one, two, three, and four years from now must match the liabilities. Therefore, we have
Note that to find [math]X[/math], we do not need the first equation.
Solving the fourth equation for [math]c[/math] yields [math]c=\frac{7811}{1.07}=7300[/math].
Substituting this value of [math]c[/math] into the third equation and solving for [math]b[/math] yields
Finally, substituting these values of [math]b[/math] and [math]c[/math] into the second equation yields [math]X=0.05(14200)+0.07(7300)=1221[/math]