ABy Admin
May 14'23
Exercise
For a collective risk model:
- The number of losses has a Poisson distribution with [math]\lambda = 2 [/math].
- The common distribution of the individual losses is:
[math]x[/math] | [math]f_X(x)[/math] |
1 | 0.6 |
2 | 0.4 |
An insurance covers aggregate losses subject to a deductible of 3.
Calculate the expected aggregate payments of the insurance.
- 0.74
- 0.79
- 0.84
- 0.89
- 0.94
ABy Admin
May 14'23
Key: A
[[math]]
\begin{aligned}
&\operatorname{E}[( S − 3)_+ ] = \operatorname{E}[ S ) − 3 + 3 f_S (0) + 2 f_S (1) + 1 f_ S (2) \\
&\operatorname{E}[ S ) = 2[0.6 + 2(0.4)] = 2.8 \\
&f_S (0) = e^{−2} , f_S (1) = e^{−2} (2)(0.6) = 1.2e^{−2} \\
&f_S(2) = e^{-2}(2)(0.4) + \frac{e^{-2}2^2}{2!}(0.6)^2 = 1.52e^{-2} \\
&\operatorname{E}[( S − 3)_+ ] = 2.8 − 3 + 3e^{−2} + 2(1.2e^{−2} ) + 1(1.52e^{−2} ) = −0.2 + 6.92e^{−2} = 0.7365
\end{aligned}
[[/math]]