⧼exchistory⧽
8 exercise(s) shown, 0 hidden
BBy Bot
Nov 03'24
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Determine whether or not each of the following infinite series converges, and evaluate it if it does.

  • [a [math]\sum_{i=0}^\infty \frac7{5^i}[/math]
  • [math]\sum_{k=1}^\infty \frac{a}{5^k}[/math]
  • [math]\sum_{n=1}^\infty \left( \frac1{2^n} + \frac1n \right)[/math]
  • [math]\sum_{j=0}^\infty \left(\frac1{2^j} - \frac1{3^j}\right)[/math]
  • [math]\sum_{i=1}^\infty \frac{5\cdot2^i+6i}{i2^i}[/math]
  • [math]\sum_{k=0}^\infty \left(3+\frac1{3^k}\right)[/math]
  • [math]\sum_{i=1}^\infty \frac{i^2-1}{i^2+1}[/math]
  • [math]\sum_{k=0}^\infty \frac{2^k+3^k}{6^k}[/math].
BBy Bot
Nov 03'24
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Consider the infinite series [math]\sum_{i=0}^\infty a_i[/math] defined by

[[math]] \cond{a_{2i} = \frac1{2^i}, & i = 0, 1, 2, \ldots ,} [[/math]]

[[math]] \cond{a_{2i+1} = 0, & i = 0, 1, 2, \ldots .} [[/math]]

Write out the sum of the first ten terms. Does the series converge? If so, to what value?

BBy Bot
Nov 03'24
[math] \newcommand{\ex}[1]{\item } \newcommand{\sx}{\item} \newcommand{\x}{\sx} \newcommand{\sxlab}[1]{} \newcommand{\xlab}{\sxlab} \newcommand{\prov}[1] {\quad #1} \newcommand{\provx}[1] {\quad \mbox{#1}} \newcommand{\intext}[1]{\quad \mbox{#1} \quad} \newcommand{\R}{\mathrm{\bf R}} \newcommand{\Q}{\mathrm{\bf Q}} \newcommand{\Z}{\mathrm{\bf Z}} \newcommand{\C}{\mathrm{\bf C}} \newcommand{\dt}{\textbf} \newcommand{\goesto}{\rightarrow} \newcommand{\ddxof}[1]{\frac{d #1}{d x}} \newcommand{\ddx}{\frac{d}{dx}} \newcommand{\ddt}{\frac{d}{dt}} \newcommand{\dydx}{\ddxof y} \newcommand{\nxder}[3]{\frac{d^{#1}{#2}}{d{#3}^{#1}}} \newcommand{\deriv}[2]{\frac{d^{#1}{#2}}{dx^{#1}}} \newcommand{\dist}{\mathrm{distance}} \newcommand{\arccot}{\mathrm{arccot\:}} \newcommand{\arccsc}{\mathrm{arccsc\:}} \newcommand{\arcsec}{\mathrm{arcsec\:}} \newcommand{\arctanh}{\mathrm{arctanh\:}} \newcommand{\arcsinh}{\mathrm{arcsinh\:}} \newcommand{\arccosh}{\mathrm{arccosh\:}} \newcommand{\sech}{\mathrm{sech\:}} \newcommand{\csch}{\mathrm{csch\:}} \newcommand{\conj}[1]{\overline{#1}} \newcommand{\mathds}{\mathbb} [/math]

Using Theorem \ref{thm 9.2.2}, show that if [math]\sum_{i=m}^\infty a_i[/math] converges and if [math]\sum_{i=m}^\infty b_i[/math] diverges, then [math]\sum_{i=m}^\infty (a_i+b_i)[/math] must diverge.

BBy Bot
Nov 03'24
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Is it true that if the series [math]\sum_{i=m}^\infty (a_i+b_i)[/math] converges, then both [math]\sum_{i=m}^\infty a_i[/math] and [math]\sum_{i=m}^\infty b_i[/math] must also converge? Give a reason for your answer.

BBy Bot
Nov 03'24
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Prove that the harmonic series [math]\sum_{k=1}^\infty \frac1k[/math] diverges using the following elementary argument. Begin by grouping the terms of the series:

[[math]] \sum_{k=1}^\infty \frac1k = 1 + \left(\frac12+\frac13\right) + \left(\frac14+\frac15+\frac16+\frac17\right) [[/math]]

[[math]] + \left(\frac18+\frac19+\frac1{10}+\frac1{11}+\frac1{12}+ \frac1{12}+\frac1{13}+\frac1{14}+\frac1{15}\right) + \cdots , [[/math]]

and observe that

[[math]] \frac12 + \frac13 \gt \frac14 + \frac14 = \frac12 , [[/math]]

[[math]] \frac14+\frac15+\frac16+\frac17 \gt \frac18+\frac18+\frac18+\frac18=\frac12, \quad \mbox{etc.} [[/math]]

BBy Bot
Nov 03'24
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Consider the infinite series [math]\sum_{k=1}^\infty \left(\frac1k - \frac1{k+1}\right)[/math]. By writing out a few terms of the sequence of partial sums, show that the series converges, and give its value.

BBy Bot
Nov 03'24
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An infinite series of the form [math]\sum_{i=m}^\infty (a_i - a_{i+1})[/math] is called a telescoping series (see Problem Exercise). Prove that it converges if and only if the sequence [math]\{ s_n \}[/math] converges. If it does converge, what is its value?

BBy Bot
Nov 03'24
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Determine whether or not each of the following infinite series converges, and evaluate it if it does.

  • [math]\sum_{k=1}^\infty \frac1{k(k+1)}[/math].
  • [math]\sum_{i=1}^\infty \frac{2i+1}{i^2(i^2+2i+1)}[/math].
  • [math]\sum_{k=1}^\infty \ln \left(\frac{k+1}k\right) = \ln \left(\frac21\right) + \ln \left(\frac32\right) + \ln \left(\frac43\right) + \cdots [/math].

(Hint: Look at Problems Exercise and Exercise.)