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| rev | Admin | (Created page with "'''Solution: A''' The number of ways choosing 5 items with exactly one defective item equals <math display = "block">5 \binom{15}{4}</math> out of a total of <math>\binom{20}{5}</math> ways of choosing 5 items. Hence the probability equals <math display = "block"> \frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402. </math>") | Jun 26'24 at 2:07 | +323 |