Exercise
ABy Admin
Jun 26'24
Answer
Solution: A
The number of ways choosing 5 items with exactly one defective item equals
[[math]]5 \binom{15}{4}[[/math]]
out of a total of [math]\binom{20}{5}[/math] ways of choosing 5 items. Hence the probability equals
[[math]]
\frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402.
[[/math]]