Exercise


ABy Admin
Jun 26'24

Answer

Solution: A

The number of ways choosing 5 items with exactly one defective item equals

[[math]]5 \binom{15}{4}[[/math]]

out of a total of [math]\binom{20}{5}[/math] ways of choosing 5 items. Hence the probability equals

[[math]] \frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402. [[/math]]

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