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revprevAdminJan 18'24 at 2:36−46m
revcurprevAdminJan 18'24 at 2:34+23
revcurprevAdminJan 18'24 at 2:34+23
revcurprevAdminJan 18'24 at 2:33+23
revcurAdmin (Created page with "'''Answer: D''' <math>\hat{S}(21.0)=\frac{59}{60} \times \frac{59-8+1-1}{59-8+1} \times \frac{51-6+7-2}{51-6+7} \times \frac{50-7+7-1}{50-7+7} \times \frac{49-6+5-1}{49-6+5}=0.8899</math> <math>\operatorname{Var}[\hat{S}(21.0)] \approx 0.8899^{2}\left(\frac{1}{60 \times 59}+\frac{1}{52 \times 51}+\frac{2}{52 \times 50}+\frac{1}{50 \times 49}+\frac{1}{48 \times 47}\right)=0.00181</math> The upper limit of the <math>80 \%</math> linear confidence interval is <math disp...")Jan 17'24 at 22:34+532