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| rev | Admin | (Created page with "'''Answer: B''' <math>L_{A}=v^{T}-0.10 \bar{a}_{\bar{T}}=\left(1+\frac{10}{6}\right) v^{T}-\frac{10}{6}</math> <math>\operatorname{Var}\left(L_{A}\right)=\left(1+\frac{10}{6}\right)^{2} \operatorname{Var}\left(v^{T}\right)=0.455 \Rightarrow \operatorname{Var}\left(v^{T}\right)=0.06398</math> <math>L_{B}=2 v^{T}-0.16 \bar{a}_{T}=\left(2+\frac{16}{6}\right) v^{T}-\frac{16}{6}</math> <math>\operatorname{Var}\left(L_{B}\right)=\left(2+\frac{16}{6}\right)^{2} \operatornam...") | Jan 20'24 at 3:11 | +575 |