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rev | Admin | (Created page with "'''Solution: E''' The accumulated values for Funds <math>X</math> and <math>Y</math> are <math>1000\left(1+\frac{k}{2}\right)^{10}</math> and <math>921.90\left(1-\frac{k}{2}\right)^{-10}</math> respectively. Equating them and solving for <math>k</math> : <math display = "block"> \begin{aligned} & 1000\left(1+\frac{k}{2}\right)^{10}=921.90\left(1-\frac{k}{2}\right)^{-10} \\ & 0.9219=\left[\left(1+\frac{k}{2}\right)\left(1-\frac{k}{2}\right)\right]^{10}=\left(1-\frac{k^2...") | Nov 17'23 at 22:56 | +595 |