Exercise


ABy Admin
Nov 17'23

Answer

Solution: E

The accumulated values for Funds [math]X[/math] and [math]Y[/math] are [math]1000\left(1+\frac{k}{2}\right)^{10}[/math] and [math]921.90\left(1-\frac{k}{2}\right)^{-10}[/math] respectively. Equating them and solving for [math]k[/math] :

[[math]] \begin{aligned} & 1000\left(1+\frac{k}{2}\right)^{10}=921.90\left(1-\frac{k}{2}\right)^{-10} \\ & 0.9219=\left[\left(1+\frac{k}{2}\right)\left(1-\frac{k}{2}\right)\right]^{10}=\left(1-\frac{k^2}{4}\right)^{10} \\ & 1-\frac{k^2}{4}=0.9919 \\ & k^2=0.0324 \\ & k=0.18 \end{aligned} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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